LinkedIn has been awash with people noticing quiet progress on Snowflake’s SQL functionality. And this challenge wants to highlight one cool feature.
Finish the following query:
with step_one as (
select 1 as numone,
2 as numtwo,
3 as numthree,
'a' as letterone,
'b' as lettertwo,
'c' as letterthree,
'+' as symbolone,
'#' as symboltwo,
';' as symbolthree
)
select * ilike ''
from step_one
The result should be:
Remember, if you want to participate:
- Sign up as a member of Frosty Friday. You can do this by clicking on the sidebar, and then going to ‘REGISTER‘
- Post your code to GitHub and make it publicly available (Check out our guide if you don’t know how to here)
- Post the URL in the comments of the challenge
8 responses to “Week 57 – Basic”
-
Nice, quick and useful. A good challenge
- Solution URL – https://github.com/ChrisHastieIW/Frosty-Friday
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Quick & easy
- Solution URL – https://github.com/canonicalized/FrostyFriday/blob/main/WEEK57.sql
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Thanks for the challenge. This, with the `group by all`, can be quite handy.
Although… so fresh out of the oven that it broke my linter…
- Solution URL – https://github.com/dsmdavid/frostyfridays-sf/blob/main/models/challenge_57.sql
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H! here is my take. Thanks
- Solution URL – https://github.com/anabelcarol/Frosty-Friday/
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Easy one with the function.
- Solution URL – https://github.com/zlzlzl2-data/FrostyFriday/blob/main/FF57_LZ.sql
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I like 🙂
- Solution URL – https://github.com/NMangera/frosty_friday/blob/main/week%2057%20-%20basic%20/ILIKE
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Another nice little feature to learn about
- Solution URL – https://github.com/ChrisBo94/FrostyFriday/blob/main/Week_57.sql
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Another handy feature!
- Solution URL – https://github.com/GerganaAK/FrostyFridays/blob/main/Week%2057%20%E2%80%93%20Basic
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